129 lines
5.7 KiB
Markdown
129 lines
5.7 KiB
Markdown
---
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id: 587d8254367417b2b2512c6f
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title: Perform a Subset Check on Two Sets of Data
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challengeType: 1
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forumTopicId: 301707
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---
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## Description
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<section id='description'>
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In this exercise we are going to perform a subset test on 2 sets of data. We will create a method on our <code>Set</code> data structure called <code>subset</code>. This will compare the first set, against the second and if the first set is fully contained within the Second then it will return true.
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For example, if <code>setA = ['a','b']</code> and <code>setB = ['a','b','c','d']</code>, then the subset of setA and setB is: <code>setA.subset(setB)</code> should be <code>true</code>.
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</section>
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## Instructions
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<section id='instructions'>
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: Your <code>Set</code> class should have a <code>subset</code> method.
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testString: assert((function(){var test = new Set(); return (typeof test.subset === 'function')})());
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- text: The first Set() was contained in the second Set
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testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setB.add('b'); setB.add('c'); setB.add('a'); setB.add('d'); var subsetSetAB = setA.subset(setB);return (subsetSetAB === true)})());
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- text: <code>['a', 'b'].subset(['a', 'b', 'c', 'd'])</code> should return <code>true</code>
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testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setB.add('a'); setB.add('b'); setB.add('c'); setB.add('d'); var subsetSetAB = setA.subset(setB); return (subsetSetAB === true)})());
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- text: <code>['a', 'b', 'c'].subset(['a', 'b'])</code> should return <code>false</code>
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testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setA.add('c'); setB.add('a'); setB.add('b'); var subsetSetAB = setA.subset(setB); return (subsetSetAB === false)})());
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- text: <code>[].subset([])</code> should return <code>true</code>
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testString: assert((function(){var setA = new Set(); var setB = new Set(); var subsetSetAB = setA.subset(setB); return (subsetSetAB === true)})());
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- text: <code>['a', 'b'].subset(['c', 'd'])</code> should return <code>false</code>
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testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setB.add('c'); setB.add('d'); var subsetSetAB = setA.subset(setB); return (subsetSetAB === false)})());
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function Set() {
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// the var collection will hold the set
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var collection = [];
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// this method will check for the presence of an element and return true or false
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this.has = function(element) {
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return (collection.indexOf(element) !== -1);
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};
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// this method will return all the values in the set
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this.values = function() {
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return collection;
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};
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// this method will add an element to the set
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this.add = function(element) {
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if(!this.has(element)){
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collection.push(element);
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return true;
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}
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return false;
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};
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// this method will remove an element from a set
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this.remove = function(element) {
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if(this.has(element)){
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var index = collection.indexOf(element);
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collection.splice(index,1);
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return true;
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}
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return false;
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};
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// this method will return the size of the collection
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this.size = function() {
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return collection.length;
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};
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// this method will return the union of two sets
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this.union = function(otherSet) {
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var unionSet = new Set();
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var firstSet = this.values();
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var secondSet = otherSet.values();
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firstSet.forEach(function(e){
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unionSet.add(e);
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});
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secondSet.forEach(function(e){
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unionSet.add(e);
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});
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return unionSet;
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};
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// this method will return the intersection of two sets as a new set
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this.intersection = function(otherSet) {
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var intersectionSet = new Set();
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var firstSet = this.values();
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firstSet.forEach(function(e){
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if(otherSet.has(e)){
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intersectionSet.add(e);
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}
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});
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return intersectionSet;
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};
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// this method will return the difference of two sets as a new set
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this.difference = function(otherSet) {
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var differenceSet = new Set();
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var firstSet = this.values();
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firstSet.forEach(function(e){
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if(!otherSet.has(e)){
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differenceSet.add(e);
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}
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});
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return differenceSet;
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};
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// change code below this line
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// change code above this line
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}
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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function Set() {var collection = []; this.has = function(e){return(collection.indexOf(e) !== -1);};this.values = function() {return collection;};this.add = function(element) {if (!this.has(element)) {collection.push(element);return true;} else {return false;}};this.remove = function(element) {if(this.has(element)) {var i = collection.indexOf(element);collection.splice(i, 1);return true;}return false;};this.size = function() {return collection.length;};this.union = function(set) {var u = new Set();var c = this.values();var s = set.values();c.forEach(function(element){u.add(element);});s.forEach(function(element){u.add(element);});return u;};this.intersection = function(set) {var i = new Set();var c = this.values();c.forEach(function(element){if(s.has(element)) i.add(element);});};this.difference = function(set) {var d = new Set();var c = this.values();c.forEach(function(e){if(!set.has(e)) d.add(e);});};this.subset = function(set) {var isSubset = true;var c = this.values();c.forEach(function(e){if(!set.has(e)) isSubset = false;});return isSubset;};}
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```
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</section>
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