61 lines
		
	
	
		
			1.8 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			61 lines
		
	
	
		
			1.8 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| title: Ackermann function
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| id: 594810f028c0303b75339acf
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| challengeType: 5
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| videoUrl: ''
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| localeTitle: 阿克曼功能
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| ---
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| 
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| ## Description
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| <section id="description"><p> Ackermann函数是递归函数的典型示例,尤其值得注意的是它不是原始递归函数。它的值增长非常快,其调用树的大小也是如此。 </p><p> Ackermann函数通常定义如下: </p> $$ A(m,n)= \ begin {cases} n + 1&\ mbox {if} m = 0 \\ A(m-1,1)&\ mbox {if} m> 0 \ mbox {和} n = 0 \\ A(m-1,A(m,n-1))&\ mbox {if} m> 0 \ mbox {和} n> 0. \ end {cases} $$ <p>它的论点永远不会消极,它总是终止。编写一个返回$ A(m,n)$的值的函数。任意精度是首选(因为函数增长如此之快),但不是必需的。 </p></section>
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| 
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| ## Instructions
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| <section id="instructions">
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| </section>
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| 
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| ## Tests
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| <section id='tests'>
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| 
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| ```yml
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| tests:
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|   - text: <code>ack</code>是一个功能。
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|     testString: 'assert(typeof ack === "function", "<code>ack</code> is a function.");'
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|   - text: '<code>ack(0, 0)</code>应该返回1。'
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|     testString: 'assert(ack(0, 0) === 1, "<code>ack(0, 0)</code> should return 1.");'
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|   - text: '<code>ack(1, 1)</code>应该返回3。'
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|     testString: 'assert(ack(1, 1) === 3, "<code>ack(1, 1)</code> should return 3.");'
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|   - text: '<code>ack(2, 5)</code>应该返回13。'
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|     testString: 'assert(ack(2, 5) === 13, "<code>ack(2, 5)</code> should return 13.");'
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|   - text: '<code>ack(3, 3)</code>应该返回61。'
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|     testString: 'assert(ack(3, 3) === 61, "<code>ack(3, 3)</code> should return 61.");'
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| 
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| ```
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| 
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| </section>
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| 
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| ## Challenge Seed
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| <section id='challengeSeed'>
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| 
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| <div id='js-seed'>
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| 
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| ```js
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| function ack (m, n) {
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|   // Good luck!
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| }
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| 
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| ```
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| 
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| </div>
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| 
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| 
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| 
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| </section>
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| 
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| ## Solution
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| <section id='solution'>
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| 
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| ```js
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| // solution required
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| ```
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| </section>
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