* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
1.3 KiB
1.3 KiB
id, title, challengeType, videoUrl, forumTopicId, dashedName
id | title | challengeType | videoUrl | forumTopicId | dashedName |
---|---|---|---|---|---|
56533eb9ac21ba0edf2244b0 | Compound Assignment With Augmented Subtraction | 1 | https://scrimba.com/c/c2Qv7AV | 16660 | compound-assignment-with-augmented-subtraction |
--description--
Like the +=
operator, -=
subtracts a number from a variable.
myVar = myVar - 5;
will subtract 5
from myVar
. This can be rewritten as:
myVar -= 5;
--instructions--
Convert the assignments for a
, b
, and c
to use the -=
operator.
--hints--
a
should equal 5
.
assert(a === 5);
b
should equal -6
.
assert(b === -6);
c
should equal 2
.
assert(c === 2);
You should use the -=
operator for each variable.
assert(code.match(/-=/g).length === 3);
You should not modify the code above the specified comment.
assert(
/var a = 11;/.test(code) && /var b = 9;/.test(code) && /var c = 3;/.test(code)
);
--seed--
--after-user-code--
(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);
--seed-contents--
var a = 11;
var b = 9;
var c = 3;
// Only change code below this line
a = a - 6;
b = b - 15;
c = c - 1;
--solutions--
var a = 11;
var b = 9;
var c = 3;
a -= 6;
b -= 15;
c -= 1;