Martin Milani 8e96fef862
fix(learn): Updated instructions for challenge solution for Reuse Patterns Using Capture Groups (#40658)
* Grammatically updated the instructions for the challenge

* Update curriculum/challenges/english/02-javascript-algorithms-and-data-structures/regular-expressions/reuse-patterns-using-capture-groups.md

Co-authored-by: Eric Leung <eric@erictleung.com>

Co-authored-by: Eric Leung <eric@erictleung.com>
2021-01-20 19:39:23 -08:00

2.7 KiB

id, title, challengeType, forumTopicId, dashedName
id title challengeType forumTopicId dashedName
587d7dbb367417b2b2512baa Reuse Patterns Using Capture Groups 1 301364 reuse-patterns-using-capture-groups

--description--

Some patterns you search for will occur multiple times in a string. It is wasteful to manually repeat that regex. There is a better way to specify when you have multiple repeat substrings in your string.

You can search for repeat substrings using capture groups. Parentheses, ( and ), are used to find repeat substrings. You put the regex of the pattern that will repeat in between the parentheses.

To specify where that repeat string will appear, you use a backslash (\) and then a number. This number starts at 1 and increases with each additional capture group you use. An example would be \1 to match the first group.

The example below matches any word that occurs twice separated by a space:

let repeatStr = "regex regex";
let repeatRegex = /(\w+)\s\1/;
repeatRegex.test(repeatStr); // Returns true
repeatStr.match(repeatRegex); // Returns ["regex regex", "regex"]

Using the .match() method on a string will return an array with the string it matches, along with its capture group.

--instructions--

Use capture groups in reRegex to match a string that consists of only the same number repeated exactly three times separated by single spaces.

--hints--

Your regex should use the shorthand character class for digits.

assert(reRegex.source.match(/\\d/));

Your regex should reuse a capture group twice.

assert(reRegex.source.match(/\\1|\\2/g).length >= 2);

Your regex should have two spaces separating the three numbers.

assert(
  reRegex.source.match(/ |\\s/g).length === 2 ||
    reRegex.source.match(/\(\\s\)(?=.*\\(1|2))/g)
);

Your regex should match "42 42 42".

assert(reRegex.test('42 42 42'));

Your regex should match "100 100 100".

assert(reRegex.test('100 100 100'));

Your regex should not match "42 42 42 42".

assert.equal('42 42 42 42'.match(reRegex.source), null);

Your regex should not match "42 42".

assert.equal('42 42'.match(reRegex.source), null);

Your regex should not match "101 102 103".

assert(!reRegex.test('101 102 103'));

Your regex should not match "1 2 3".

assert(!reRegex.test('1 2 3'));

Your regex should match "10 10 10".

assert(reRegex.test('10 10 10'));

--seed--

--seed-contents--

let repeatNum = "42 42 42";
let reRegex = /change/; // Change this line
let result = reRegex.test(repeatNum);

--solutions--

let repeatNum = "42 42 42";
let reRegex = /^(\d+)\s\1\s\1$/;
let result = reRegex.test(repeatNum);