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freeCodeCamp/curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-474-last-digits-of-divisors.english.md
Oliver Eyton-Williams bd68b70f3d Feat: hide blocks not challenges (#39504)
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Co-authored-by: Ahmad Abdolsaheb <ahmad.abdolsaheb@gmail.com>

* feat: hide blocks not challenges

Co-authored-by: Ahmad Abdolsaheb <ahmad.abdolsaheb@gmail.com>

Co-authored-by: Ahmad Abdolsaheb <ahmad.abdolsaheb@gmail.com>
2020-09-03 15:07:40 -07:00

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id, challengeType, title, forumTopicId
id challengeType title forumTopicId
5900f5471000cf542c510059 5 Problem 474: Last digits of divisors 302151

Description

For a positive integer n and digits d, we define F(n, d) as the number of the divisors of n whose last digits equal d. For example, F(84, 4) = 3. Among the divisors of 84 (1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84), three of them (4, 14, 84) have the last digit 4.

We can also verify that F(12!, 12) = 11 and F(50!, 123) = 17888.

Find F(106!, 65432) modulo (1016 + 61).

Instructions

Tests

tests:
  - text: <code>euler474()</code> should return 9690646731515010.
    testString: assert.strictEqual(euler474(), 9690646731515010);

Challenge Seed

function euler474() {
  // Good luck!
  return true;
}

euler474();

Solution

// solution required