* feat(curriculum): Add Basic JS Scrimba links * Fix: Add missing video url. * fix: update videoUrl
2.3 KiB
2.3 KiB
id, title, challengeType, videoUrl
id | title | challengeType | videoUrl |
---|---|---|---|
56533eb9ac21ba0edf2244e1 | Nesting For Loops | 1 | https://scrimba.com/c/cRn6GHM |
Description
var arr = [This outputs each sub-element in
[1,2], [3,4], [5,6]
];
for (var i=0; i < arr.length; i++) {
for (var j=0; j < arr[i].length; j++) {
console.log(arr[i][j]);
}
}
arr
one at a time. Note that for the inner loop, we are checking the .length
of arr[i]
, since arr[i]
is itself an array.
Instructions
multiplyAll
so that it multiplies the product
variable by each number in the sub-arrays of arr
Tests
tests:
- text: <code>multiplyAll([[1],[2],[3]])</code> should return <code>6</code>
testString: assert(multiplyAll([[1],[2],[3]]) === 6, '<code>multiplyAll([[1],[2],[3]])</code> should return <code>6</code>');
- text: <code>multiplyAll([[1,2],[3,4],[5,6,7]])</code> should return <code>5040</code>
testString: assert(multiplyAll([[1,2],[3,4],[5,6,7]]) === 5040, '<code>multiplyAll([[1,2],[3,4],[5,6,7]])</code> should return <code>5040</code>');
- text: <code>multiplyAll([[5,1],[0.2, 4, 0.5],[3, 9]])</code> should return <code>54</code>
testString: assert(multiplyAll([[5,1],[0.2, 4, 0.5],[3, 9]]) === 54, '<code>multiplyAll([[5,1],[0.2, 4, 0.5],[3, 9]])</code> should return <code>54</code>');
Challenge Seed
function multiplyAll(arr) {
var product = 1;
// Only change code below this line
// Only change code above this line
return product;
}
// Modify values below to test your code
multiplyAll([[1,2],[3,4],[5,6,7]]);
Solution
function multiplyAll(arr) {
var product = 1;
for (var i = 0; i < arr.length; i++) {
for (var j = 0; j < arr[i].length; j++) {
product *= arr[i][j];
}
}
return product;
}
multiplyAll([[1,2],[3,4],[5,6,7]]);