freeCodeCamp/iterate-odd-numbers-with-a-for-loop.english.md at deb24f77b61fb96b822c640dff1b205f6ed1cbb0

Randell Dawson 3ec1fe8ea7 feat: add forumTopicId to challenge frontmatter [pre-existing]

This commit adds the pre-existing challenge guide topics in the
forum to the forntmatter of their challenge markdown files.

2019-08-05 22:14:37 +05:30

1.7 KiB

Raw Blame History

id, title, challengeType, videoUrl, forumTopicId

id	title	challengeType	videoUrl	forumTopicId
56104e9e514f539506016a5c	Iterate Odd Numbers With a For Loop	1	https://scrimba.com/c/cm8n7T9	18212

Description

For loops don't have to iterate one at a time. By changing our final-expression, we can count by even numbers. We'll start at i = 0 and loop while i < 10. We'll increment i by 2 each loop with i += 2.

var ourArray = [];
for (var i = 0; i < 10; i += 2) {
  ourArray.push(i);
}

ourArray will now contain [0,2,4,6,8]. Let's change our initialization so we can count by odd numbers.

Instructions

Push the odd numbers from 1 through 9 to myArray using a for loop.

Tests

tests:
  - text: You should be using a <code>for</code> loop for this.
    testString: assert(code.match(/for\s*\(/g).length > 1);
  - text: <code>myArray</code> should equal <code>[1,3,5,7,9]</code>.
    testString: assert.deepEqual(myArray, [1,3,5,7,9]);

Challenge Seed

// Example
var ourArray = [];

for (var i = 0; i < 10; i += 2) {
  ourArray.push(i);
}

// Setup
var myArray = [];

// Only change code below this line.

After Test

if(typeof myArray !== "undefined"){(function(){return myArray;})();}

Solution

var ourArray = [];
for (var i = 0; i < 10; i += 2) {
  ourArray.push(i);
}
var myArray = [];
for (var i = 1; i < 10; i += 2) {
  myArray.push(i);
}

1.7 KiB Raw Blame History