* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
1.9 KiB
1.9 KiB
id, title, challengeType, forumTopicId, dashedName
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
afcc8d540bea9ea2669306b6 | 重复输出字符串 | 5 | 16041 | repeat-a-string-repeat-a-string |
--description--
为num
times(第二个参数)重复给定的字符串str
(第一个参数)。如果num
不是正数,则返回空字符串。如果卡住,请记得使用Read-Search-Ask 。编写自己的代码。
将一个给定的字符串 str
(第一个参数)重复输出 num
(第二个参数)次。如果 num
不是正数,返回空字符串。在这个挑战中,请不要使用 JavaScript 内置的 .repeat()
方法。
--hints--
repeatStringNumTimes("*", 3)
应返回 "***"
。
assert(repeatStringNumTimes('*', 3) === '***');
repeatStringNumTimes("abc", 3)
应返回 "abcabcabc"
。
assert(repeatStringNumTimes('abc', 3) === 'abcabcabc');
repeatStringNumTimes("abc", 4)
应返回 "abcabcabcabc"
。
assert(repeatStringNumTimes('abc', 4) === 'abcabcabcabc');
repeatStringNumTimes("abc", 1)
应返回 "abc"
。
assert(repeatStringNumTimes('abc', 1) === 'abc');
repeatStringNumTimes("*", 8)
应返回 "********"
。
assert(repeatStringNumTimes('*', 8) === '********');
repeatStringNumTimes("abc", -2)
应返回 ""
。
assert(repeatStringNumTimes('abc', -2) === '');
不应使用内置的 repeat()
方法。
assert(!/\.repeat/g.test(code));
repeatStringNumTimes("abc", 0)
应返回 ""
。
assert(repeatStringNumTimes('abc', 0) === '');
--seed--
--seed-contents--
function repeatStringNumTimes(str, num) {
return str;
}
repeatStringNumTimes("abc", 3);
--solutions--
function repeatStringNumTimes(str, num) {
if (num < 1) return '';
return num === 1 ? str : str + repeatStringNumTimes(str, num-1);
}
repeatStringNumTimes("abc", 3);