* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2.1 KiB
2.1 KiB
id, title, challengeType, forumTopicId, dashedName
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
579e2a2c335b9d72dd32e05c | Slice 与 Splice | 5 | 301148 | slice-and-splice |
--description--
本挑战的输入参数为两个数组和一个索引值。
请使用数组的 slice
和 splice
方法,将第一个数组中的所有元素依次复制到第二个数组中。
请注意,你需要从第二个数组索引值为 n
(函数的第三个参数)的地方开始插入。
最后,请返回插入元素后的数组。作为输入参数的两个数组在函数执行前后应保持不变。
--hints--
frankenSplice([1, 2, 3], [4, 5], 1)
应返回 [4, 1, 2, 3, 5]
。
assert.deepEqual(frankenSplice([1, 2, 3], [4, 5], 1), [4, 1, 2, 3, 5]);
frankenSplice([1, 2], ["a", "b"], 1)
应返回 ["a", 1, 2, "b"]
。
assert.deepEqual(frankenSplice(testArr1, testArr2, 1), ['a', 1, 2, 'b']);
frankenSplice(["claw", "tentacle"], ["head", "shoulders", "knees", "toes"], 2)
应返回 ["head", "shoulders", "claw", "tentacle", "knees", "toes"]
。
assert.deepEqual(
frankenSplice(
['claw', 'tentacle'],
['head', 'shoulders', 'knees', 'toes'],
2
),
['head', 'shoulders', 'claw', 'tentacle', 'knees', 'toes']
);
第一个数组中的所有元素都应按原始顺序添加到第二个数组中。
assert.deepEqual(frankenSplice([1, 2, 3, 4], [], 0), [1, 2, 3, 4]);
函数运行后,第一个数组应保持不变。
frankenSplice(testArr1, testArr2, 1);
assert.deepEqual(testArr1, [1, 2]);
函数运行后,第二个数组应保持不变。
frankenSplice(testArr1, testArr2, 1);
assert.deepEqual(testArr2, ['a', 'b']);
--seed--
--after-user-code--
let testArr1 = [1, 2];
let testArr2 = ["a", "b"];
--seed-contents--
function frankenSplice(arr1, arr2, n) {
return arr2;
}
frankenSplice([1, 2, 3], [4, 5, 6], 1);
--solutions--
function frankenSplice(arr1, arr2, n) {
// It's alive. It's alive!
let result = arr2.slice();
for (let i = 0; i < arr1.length; i++) {
result.splice(n+i, 0, arr1[i]);
}
return result;
}
frankenSplice([1, 2, 3], [4, 5], 1);