Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

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---
id: 5900f3a11000cf542c50feb4
title: 问题53组合选择
challengeType: 5
videoUrl: ''
dashedName: problem-53-combinatoric-selections
---
# --description--
有十种方法从五种中选择三种12345123,124,125,134,135,145,234,235,245和345在组合学中我们使用符号5C3 = 10.一般来说,
nCr = nrn-r 其中r≤nn = n×n-1×...×3×2×1和0 = 1。
直到n = 23一个值超过一百万23C10 = 1144066.对于1≤n≤100nCr的多少不一定是不同的值大于一百万
# --hints--
`combinatoricSelections(1000)`应返回4626。
```js
assert.strictEqual(combinatoricSelections(1000), 4626);
```
`combinatoricSelections(10000)`应该返回4431。
```js
assert.strictEqual(combinatoricSelections(10000), 4431);
```
`combinatoricSelections(100000)`应返回4255。
```js
assert.strictEqual(combinatoricSelections(100000), 4255);
```
`combinatoricSelections(1000000)`应该返回4075。
```js
assert.strictEqual(combinatoricSelections(1000000), 4075);
```
# --seed--
## --seed-contents--
```js
function combinatoricSelections(limit) {
return 1;
}
combinatoricSelections(1000000);
```
# --solutions--
```js
function combinatoricSelections(limit) {
const factorial = n =>
Array.apply(null, { length: n })
.map((_, i) => i + 1)
.reduce((p, c) => p * c, 1);
let result = 0;
const nMax = 100;
for (let n = 1; n <= nMax; n++) {
for (let r = 0; r <= n; r++) {
if (factorial(n) / (factorial(r) * factorial(n - r)) >= limit)
result++;
}
}
return result;
}
```