ee1e8abd87
* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
1.3 KiB
1.3 KiB
id, title, challengeType, videoUrl, forumTopicId, dashedName
| id | title | challengeType | videoUrl | forumTopicId | dashedName |
|---|---|---|---|---|---|
| 56533eb9ac21ba0edf2244b2 | Compound Assignment With Augmented Division | 1 | https://scrimba.com/c/c2QvKT2 | 16659 | compound-assignment-with-augmented-division |
--description--
The /= operator divides a variable by another number.
myVar = myVar / 5;
Will divide myVar by 5. This can be rewritten as:
myVar /= 5;
--instructions--
Convert the assignments for a, b, and c to use the /= operator.
--hints--
a should equal 4.
assert(a === 4);
b should equal 27.
assert(b === 27);
c should equal 3.
assert(c === 3);
You should use the /= operator for each variable.
assert(code.match(/\/=/g).length === 3);
You should not modify the code above the specified comment.
assert(
/var a = 48;/.test(code) &&
/var b = 108;/.test(code) &&
/var c = 33;/.test(code)
);
--seed--
--after-user-code--
(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);
--seed-contents--
var a = 48;
var b = 108;
var c = 33;
// Only change code below this line
a = a / 12;
b = b / 4;
c = c / 11;
--solutions--
var a = 48;
var b = 108;
var c = 33;
a /= 12;
b /= 4;
c /= 11;