Co-authored-by: Oliver Eyton-Williams <ojeytonwilliams@gmail.com> Co-authored-by: Kristofer Koishigawa <scissorsneedfoodtoo@gmail.com> Co-authored-by: Beau Carnes <beaucarnes@gmail.com>
		
			
				
	
	
		
			113 lines
		
	
	
		
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			113 lines
		
	
	
		
			3.7 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f37e1000cf542c50fe91
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| challengeType: 5
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| isHidden: false
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| title: 'Problem 18: Maximum path sum I'
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| forumTopicId: 301815
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| ---
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| 
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| ## Description
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| <section id='description'>
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| 
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| By starting at the top of the triangle below and moving to adjacent numbers on the row below, the maximum total from top to bottom is 23.
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| 
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| <span style='display: block; text-align: center;'>
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|   <strong style='color: red;'>3</strong><br>
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|   <strong style='color: red;'>7</strong> 4<br>
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|   2 <strong style='color: red;'>4</strong> 6<br>
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|   8 5 <strong style='color: red;'>9</strong> 3
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| </span>
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| 
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| That is, 3 + 7 + 4 + 9 = 23.
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| 
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| Find the maximum total from top to bottom of the triangle below:
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| 
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| <span style='display: block; text-align: center;'>75<br>95 64<br>17 47 82<br>18 35 87 10<br>20 04 82 47 65<br>19 01 23 75 03 34<br>88 02 77 73 07 63 67<br>99 65 04 28 06 16 70 92<br>41 41 26 56 83 40 80 70 33<br>41 48 72 33 47 32 37 16 94 29<br>53 71 44 65 25 43 91 52 97 51 14<br>70 11 33 28 77 73 17 78 39 68 17 57<br>91 71 52 38 17 14 91 43 58 50 27 29 48<br>63 66 04 68 89 53 67 30 73 16 69 87 40 31<br>04 62 98 27 23 09 70 98 73 93 38 53 60 04 23</span>
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| 
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| **NOTE:** As there are only 16384 routes, it is possible to solve this problem by trying every route. However, Problem 67, is the same challenge with a triangle containing one-hundred rows; it cannot be solved by brute force, and requires a clever method! ;o)
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| 
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| </section>
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| 
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| ## Instructions
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| <section id='instructions'>
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| 
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| </section>
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| 
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| ## Tests
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| <section id='tests'>
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| 
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| ```yml
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| tests:
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|   - text: <code>maximumPathSumI(testTriangle)</code> should return a number.
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|     testString: assert(typeof maximumPathSumI(testTriangle) === 'number');
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|   - text: <code>maximumPathSumI(testTriangle)</code> should return 23.
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|     testString: assert.strictEqual(maximumPathSumI(testTriangle), 23);
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|   - text: <code>maximumPathSumI(numTriangle)</code> should return 1074.
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|     testString: assert.strictEqual(maximumPathSumI(numTriangle), 1074);
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| 
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| ```
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| 
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| </section>
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| 
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| ## Challenge Seed
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| <section id='challengeSeed'>
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| 
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| <div id='js-seed'>
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| 
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| ```js
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| function maximumPathSumI(triangle) {
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|   // Good luck!
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|   return true;
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| }
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| 
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| const testTriangle = [[3, 0, 0, 0],
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|                       [7, 4, 0, 0],
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|                       [2, 4, 6, 0],
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|                       [8, 5, 9, 3]];
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| 
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| maximumPathSumI(testTriangle);
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| ```
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| 
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| </div>
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| 
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| ### Before Test
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| <div id='js-setup'>
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| 
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| ```js
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| const numTriangle = [[75, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [95, 64, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [17, 47, 82, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [18, 35, 87, 10, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [20, 4, 82, 47, 65, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [19, 1, 23, 75, 3, 34, 0, 0, 0, 0, 0, 0, 0, 0, 0], [88, 2, 77, 73, 7, 63, 67, 0, 0, 0, 0, 0, 0, 0, 0], [99, 65, 4, 28, 6, 16, 70, 92, 0, 0, 0, 0, 0, 0, 0], [41, 41, 26, 56, 83, 40, 80, 70, 33, 0, 0, 0, 0, 0, 0], [41, 48, 72, 33, 47, 32, 37, 16, 94, 29, 0, 0, 0, 0, 0], [53, 71, 44, 65, 25, 43, 91, 52, 97, 51, 14, 0, 0, 0, 0], [70, 11, 33, 28, 77, 73, 17, 78, 39, 68, 17, 57, 0, 0, 0], [91, 71, 52, 38, 17, 14, 91, 43, 58, 50, 27, 29, 48, 0, 0], [63, 66, 4, 68, 89, 53, 67, 30, 73, 16, 69, 87, 40, 31, 0], [4, 62, 98, 27, 23, 9, 70, 98, 73, 93, 38, 53, 60, 4, 23]];
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| ```
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| 
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| </div>
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| 
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| 
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| </section>
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| 
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| ## Solution
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| <section id='solution'>
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| 
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| 
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| ```js
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| const testTriangle = [[3, 0, 0, 0],
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|   [7, 4, 0, 0],
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|   [2, 4, 6, 0],
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|   [8, 5, 9, 3]];
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| 
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| function maximumPathSumI(triangle) {
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|   let maxSum = triangle.slice();
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| 
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|   for (let i = triangle.length - 1; i > 0; i--) {
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|     let currentRow = maxSum[i];
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|     let previousRow = maxSum[i - 1];
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|     const temp = [];
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|     for (let j = 0; j < i; j++) {
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|       temp.push(Math.max((currentRow[j] + previousRow[j]), (currentRow[j + 1] + previousRow[j])));
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|     }
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|     maxSum[i - 1] = temp;
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|     maxSum.pop();
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|   }
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|   return maxSum[0][0];
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| }
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| ```
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| 
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| </section>
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