freeCodeCamp/problem-474-last-digits-of-divisors.english.md at f1c9b08cf322e4268a0a31ae9b5d75bf3cfce7d1

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Oliver Eyton-Williams f1c9b08cf3 fix(curriculum): add isHidden: false to challenges

This includes certificates (where it does nothing), but does not
include any translations.

2020-05-25 16:25:19 +05:30

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id, challengeType, isHidden, title, forumTopicId

id	challengeType	isHidden	title	forumTopicId
5900f5471000cf542c510059	5	false	Problem 474: Last digits of divisors	302151

Description

For a positive integer n and digits d, we define F(n, d) as the number of the divisors of n whose last digits equal d. For example, F(84, 4) = 3. Among the divisors of 84 (1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84), three of them (4, 14, 84) have the last digit 4.

We can also verify that F(12!, 12) = 11 and F(50!, 123) = 17888.

Find F(106!, 65432) modulo (1016 + 61).

Instructions

Tests

tests:
  - text: <code>euler474()</code> should return 9690646731515010.
    testString: assert.strictEqual(euler474(), 9690646731515010);

Challenge Seed

function euler474() {
  // Good luck!
  return true;
}

euler474();

Solution

// solution required

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