100 lines
		
	
	
		
			3.1 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			100 lines
		
	
	
		
			3.1 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 587d8253367417b2b2512c6d
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| title: Perform an Intersection on Two Sets of Data
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| challengeType: 1
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| videoUrl: ''
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| localeTitle: 在两组数据上执行交集
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| ---
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| 
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| ## Description
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| <section id="description">在本练习中,我们将对两组数据执行交集。我们将在我们的<code>Set</code>数据结构上创建一个名为<code>intersection</code> 。集合的交集表示两个或更多集合共有的所有值。此方法应将另一个<code>Set</code>作为参数,并返回两个集合的<code>intersection</code> 。例如,如果<code>setA = ['a','b','c']</code>和<code>setB = ['a','b','d','e']</code> ,则setA和setB的交集为: <code>setA.intersection(setB) = ['a', 'b']</code> 。 </section>
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| 
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| ## Instructions
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| <section id="instructions">
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| </section>
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| 
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| ## Tests
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| <section id='tests'>
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| 
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| ```yml
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| tests:
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|   - text: 您的<code>Set</code>类应该有一个<code>intersection</code>方法。
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|     testString: 'assert(function(){var test = new Set(); return (typeof test.intersection === "function")}, "Your <code>Set</code> class should have a <code>intersection</code> method.");'
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|   - text: 收回了适当的收藏
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|     testString: 'assert(function(){  var setA = new Set();  var setB = new Set();  setA.add("a");  setA.add("b");  setA.add("c");  setB.add("c");  setB.add("d");  var intersectionSetAB = setA.intersection(setB); return (intersectionSetAB.size() === 1 && intersectionSetAB.values()[0] === "c")}, "The proper collection was returned");'
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| 
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| ```
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| 
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| </section>
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| 
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| ## Challenge Seed
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| <section id='challengeSeed'>
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| 
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| <div id='js-seed'>
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| 
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| ```js
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| function Set() {
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|     // the var collection will hold the set
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|     var collection = [];
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|     // this method will check for the presence of an element and return true or false
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|     this.has = function(element) {
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|         return (collection.indexOf(element) !== -1);
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|     };
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|     // this method will return all the values in the set
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|     this.values = function() {
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|         return collection;
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|     };
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|    // this method will add an element to the set
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|     this.add = function(element) {
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|         if(!this.has(element)){
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|             collection.push(element);
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|             return true;
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|         }
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|         return false;
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|     };
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|     // this method will remove an element from a set
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|     this.remove = function(element) {
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|         if(this.has(element)){
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|            var index = collection.indexOf(element);
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|             collection.splice(index,1);
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|             return true;
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|         }
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|         return false;
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|     };
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|     // this method will return the size of the collection
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|     this.size = function() {
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|         return collection.length;
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|     };
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|     // this method will return the union of two sets
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|     this.union = function(otherSet) {
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|         var unionSet = new Set();
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|         var firstSet = this.values();
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|         var secondSet = otherSet.values();
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|         firstSet.forEach(function(e){
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|             unionSet.add(e);
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|         });
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|         secondSet.forEach(function(e){
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|             unionSet.add(e);
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|         });
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|         return unionSet;
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|     };
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|     // change code below this line
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|     // change code above this line
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| }
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| 
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| ```
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| 
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| </div>
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| 
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| 
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| 
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| </section>
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| 
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| ## Solution
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| <section id='solution'>
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| 
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| ```js
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| // solution required
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| ```
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| </section>
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