94 lines
		
	
	
		
			2.2 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			94 lines
		
	
	
		
			2.2 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
---
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id: 5900f3931000cf542c50fea5
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title: 'Problem 38: Pandigital multiples'
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challengeType: 5
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forumTopicId: 302042
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dashedName: problem-38-pandigital-multiples
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---
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# --description--
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Take the number 192 and multiply it by each of 1, 2, and 3:
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<div style='margin-left: 4em;'>
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  192 × 1 = 192<br>
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  192 × 2 = 384<br>
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  192 × 3 = 576<br>
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</div>
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By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1, 2, 3).
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The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1, 2, 3, 4, 5).
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What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1, 2, ... , `n`) where `n` > 1?
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# --hints--
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`pandigitalMultiples()` should return a number.
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```js
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assert(typeof pandigitalMultiples() === 'number');
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```
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`pandigitalMultiples()` should return 932718654.
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```js
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assert.strictEqual(pandigitalMultiples(), 932718654);
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```
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# --seed--
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## --seed-contents--
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```js
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function pandigitalMultiples() {
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  return true;
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}
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pandigitalMultiples();
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```
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# --solutions--
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```js
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function pandigitalMultiples() {
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  function get9DigitConcatenatedProduct(num) {
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    // returns false if concatenated product is not 9 digits
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    let concatenatedProduct = num.toString();
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    for (let i = 2; concatenatedProduct.length < 9; i++) {
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      concatenatedProduct += num * i;
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    }
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    return concatenatedProduct.length === 9 ? concatenatedProduct : false;
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  }
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  function is1to9Pandigital(num) {
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    const numStr = num.toString();
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    // check if length is not 9
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    if (numStr.length !== 9) {
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      return false;
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    }
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    // check if pandigital
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    for (let i = 9; i > 0; i--) {
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      if (numStr.indexOf(i.toString()) === -1) {
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        return false;
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      }
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    }
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    return true;
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  }
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  let largestNum = 0;
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  for (let i = 9999; i >= 9000; i--) {
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    const concatenatedProduct =  get9DigitConcatenatedProduct(i);
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    if (is1to9Pandigital(concatenatedProduct) && concatenatedProduct > largestNum) {
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      largestNum = parseInt(concatenatedProduct);
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      break;
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    }
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  }
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  return largestNum;
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}
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```
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