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freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/basic-javascript/compound-assignment-with-augmented-subtraction.md
Nicholas Carrigan (he/him) aff0ea700d chore(i8n,learn): processed translations (#41350)
* chore(i8n,learn): processed translations

* fix: restore deleted test

* fix: revert casing change

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id, title, challengeType, videoUrl, forumTopicId, dashedName
id title challengeType videoUrl forumTopicId dashedName
56533eb9ac21ba0edf2244b0 复合赋值之 -= 1 https://scrimba.com/c/c2Qv7AV 16660 compound-assignment-with-augmented-subtraction

--description--

+= 操作符类似,-= 操作符用来对一个变量进行减法赋值操作。

myVar = myVar - 5;

变量 myVar 等于自身减去 5 的值。 也可以写成这种形式:

myVar -= 5;

--instructions--

使用 -= 操作符对 abc 实现相减赋值。

--hints--

a 应该等于 5

assert(a === 5);

b 应该等于 -6

assert(b === -6);

c 应该等于 2

assert(c === 2);

应该对每个变量使用 -= 操作符。

assert(code.match(/-=/g).length === 3);

不要修改注释上面的代码。

assert(
  /var a = 11;/.test(code) && /var b = 9;/.test(code) && /var c = 3;/.test(code)
);

--seed--

--after-user-code--

(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);

--seed-contents--

var a = 11;
var b = 9;
var c = 3;

// Only change code below this line
a = a - 6;
b = b - 15;
c = c - 1;

--solutions--

var a = 11;
var b = 9;
var c = 3;

a -= 6;
b -= 15;
c -= 1;