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			70 lines
		
	
	
		
			1.1 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			70 lines
		
	
	
		
			1.1 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f51d1000cf542c51002f
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| challengeType: 5
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| title: 'Problem 433: Steps in Euclid"s algorithm'
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| videoUrl: ''
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| localeTitle: 问题433:欧几里得算法的步骤
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| ---
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| 
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| ## Description
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| <section id="description">
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| 设E(x0,y0)为用Euclid算法确定x0和y0的最大公约数所需要的步数。 更正式地说:x1 = y0,y1 = x0 mod y0xn = yn-1,yn = xn-1 mod yn-1
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| E(x0,y0)是最小的n,因此yn = 0。
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| 
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| 
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| 我们有E(1,1)= 1,E(10,6)= 3和E(6,10)= 4。
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| 
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| 
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| 将S(N)定义为1≤x,y≤N的E(x,y)之和。
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| 我们有S(1)= 1,S(10)= 221和S(100)= 39826。
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| 
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| 
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| 求S(5·106)。
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| </section>
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| 
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| ## Instructions
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| <section id="instructions">
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| </section>
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| 
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| ## Tests
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| <section id='tests'>
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| 
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| ```yml
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| tests:
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|   - text: <code>euler433()</code>应该返回326624372659664。
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|     testString: assert.strictEqual(euler433(), 326624372659664);
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| 
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| ```
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| 
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| </section>
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| 
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| ## Challenge Seed
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| <section id='challengeSeed'>
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| 
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| <div id='js-seed'>
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| 
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| ```js
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| function euler433() {
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|   // Good luck!
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|   return true;
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| }
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| 
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| euler433();
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| 
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| ```
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| 
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| </div>
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| 
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| 
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| 
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| </section>
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| 
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| ## Solution
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| <section id='solution'>
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| 
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| ```js
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| // solution required
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| ```
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| 
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| /section>
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