90 lines
		
	
	
		
			2.5 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			90 lines
		
	
	
		
			2.5 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ## What's pseudorandom number generation?
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| 1. Numbers appear to be randomly generated but in reality they are not *CORRECT*
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| 2. Generating random numbers according to the physical laws
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| 3. Generating pseudo even and odd numbers
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| 
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| > **1:** Computers are deterministic machines. They can't generate truly random numbers (unlike actual physical processes).
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| 
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| 
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| ## What's a seed number?
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| 1. Exchanging of random numbers between two computers
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| 2. It's used to getting a random number between 0 and the seed number
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| 3. It's used initialize a pseduorandom number generator *CORRECT*
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| 
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| 
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| ## Which package is used to generate pseudorandom numbers in Go?
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| 1. pseudorand
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| 2. rand *CORRECT*
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| 3. random
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| 4. randomizer
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| 
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| 
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| ## What does [0, 5) mean?
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| 1. A range of numbers between 0 and 5 (excluding 5) *CORRECT*
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| 2. A range of numbers between 0 and 5 (including 5)
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| 3. Just 0 and 5
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| 4. Just 0 and 4
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| 
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| > **1:** Right. The square-brace means: "inclusion". The parenthesis means: "exclusion". So, [0, 5] means: 0, 1, 2, 3, 4. It's called the "mathematical interval notation".
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| 
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| 
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| ## Why this function call would not work?
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| ```go
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| rand.Intn(0)
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| ```
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| 1. First you should seed it
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| 2. It expects two arguments
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| 3. Intn works within a range of [0, 0). So, it doesn't make sense to include 0 and not include 0 at the same time. *CORRECT*
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| 
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| > **1:** That's not the cause of this error. You don't always have to seed it.
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| > **2:** No, it does not.
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| 
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| 
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| ## What does this program print?
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| Note that, each seed number below returns pseudorandom numbers as these:
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| 
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| ```
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| Seed: 0
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|   3 3 6 8 4 1 9 3 6 6
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| 
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| Seed: 1
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|   1 1 9 3 2 4 7 6 6 6
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| 
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| Seed: 2
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|   10 1 2 2 0 6 4 1 0 5
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| ```
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| 
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| Here's the program:
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| 
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| ```go
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| package main
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| 
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| import (
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| 	"fmt"
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| 	"math/rand"
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| )
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| 
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| func main() {
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| 	for i := 0; i < 3; i++ {
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| 		rand.Seed(int64(i))
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| 		fmt.Print(rand.Intn(11), " ")
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| 		fmt.Print(rand.Intn(11), " ")
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| 	}
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| }
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| ```
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| 1. 3 1 10 3 1 1
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| 2. 3 6 1 6 10 5
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| 3. 1 10 1 1 3 3
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| 4.  3 3 1 1 10 1 *CORRECT*
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| 
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| > **4:** The numbers are determined depending on the seed number. So, this loop, seeds the pseudorandom generator with 0, 1, and 2 respectively.
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| > 
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| > And, after each seed, it calls Intn twice to generate two random numbers.
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| > 
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| > So, if you look at the result, 3 3 is the first two numbers of Seed: 0. 1 1 for Seed: 1. And, 10 1 for Seed: 2.
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| 
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| 
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| ## What you should do if you want the pseudorandom generator to produce random numbers each time you run your program?
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| 1. You need to seed it like this: rand.Seed(rand.Random)
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| 2. You need to seed it like this: rand.Seed(time.Now().UnixNano()) *CORRECT*
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| 3. You need to seed it like this: rand.Seed(time.Now()) |