fix(curriculum): clean-up Project Euler 121-140 (#42731)

* fix: clean-up Project Euler 121-140

* fix: corrections from review

Co-authored-by: Sem Bauke <46919888+Sembauke@users.noreply.github.com>

* fix: missing backticks

Co-authored-by: Kristofer Koishigawa <scissorsneedfoodtoo@gmail.com>

* fix: corrections from review

Co-authored-by: Tom <20648924+moT01@users.noreply.github.com>

* fix: missing delimiter

Co-authored-by: Sem Bauke <46919888+Sembauke@users.noreply.github.com>
Co-authored-by: Kristofer Koishigawa <scissorsneedfoodtoo@gmail.com>
Co-authored-by: Tom <20648924+moT01@users.noreply.github.com>
This commit is contained in:
gikf
2021-07-16 21:38:37 +02:00
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parent dc3b2508e4
commit 7907f62337
20 changed files with 314 additions and 185 deletions

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@ -10,14 +10,24 @@ dashedName: problem-126-cuboid-layers
The minimum number of cubes to cover every visible face on a cuboid measuring 3 x 2 x 1 is twenty-two.
If we then add a second layer to this solid it would require forty-six cubes to cover every visible face, the third layer would require seventy-eight cubes, and the fourth layer would require one-hundred and eighteen cubes to cover every visible face. However, the first layer on a cuboid measuring 5 x 1 x 1 also requires twenty-two cubes; similarly the first layer on cuboids measuring 5 x 3 x 1, 7 x 2 x 1, and 11 x 1 x 1 all contain forty-six cubes. We shall define C(n) to represent the number of cuboids that contain n cubes in one of its layers. So C(22) = 2, C(46) = 4, C(78) = 5, and C(118) = 8. It turns out that 154 is the least value of n for which C(n) = 10. Find the least value of n for which C(n) = 1000.
<img class="img-responsive center-block" alt="3x2x1 cuboid covered by twenty-two 1x1x1 cubes" src="https://cdn.freecodecamp.org/curriculum/project-euler/cuboid-layers.png" style="background-color: white; padding: 10px;">
If we add a second layer to this solid it would require forty-six cubes to cover every visible face, the third layer would require seventy-eight cubes, and the fourth layer would require one-hundred and eighteen cubes to cover every visible face.
However, the first layer on a cuboid measuring 5 x 1 x 1 also requires twenty-two cubes; similarly, the first layer on cuboids measuring 5 x 3 x 1, 7 x 2 x 1, and 11 x 1 x 1 all contain forty-six cubes.
We shall define $C(n)$ to represent the number of cuboids that contain $n$ cubes in one of its layers. So $C(22) = 2$, $C(46) = 4$, $C(78) = 5$, and $C(118) = 8$.
It turns out that 154 is the least value of $n$ for which $C(n) = 10$.
Find the least value of $n$ for which $C(n) = 1000$.
# --hints--
`euler126()` should return 18522.
`cuboidLayers()` should return `18522`.
```js
assert.strictEqual(euler126(), 18522);
assert.strictEqual(cuboidLayers(), 18522);
```
# --seed--
@ -25,12 +35,12 @@ assert.strictEqual(euler126(), 18522);
## --seed-contents--
```js
function euler126() {
function cuboidLayers() {
return true;
}
euler126();
cuboidLayers();
```
# --solutions--