Equation symbol changes and formatting changes (#22049)

* Equation symbol changes and formatting changes

-Initially, SQRT(value) does not actually create a square root symbol, so I decided to use replace SQRT( ) with √ next to the number, which has successfully created the square root symbol to the left of the number.
-Given that the information of the article was unorganized through jumbled information, I decided to use the paragraph tag, <p>, to make the article have an organized structure.
-I also used the biggest headline tag, <h1>, to outline the topics of square roots 
-Given that '-----' was not an effective method of creating fractions, I decided to use the fraction slash tag, "&frasl;", the superscript element, <sup>, and the subscript element, <sub>, in order to create suitable fractions

* Removing unnecessary coding and editing content

-I just double checked this content, and realized that there were a couple of mistakes such as an extra heading, putting a square root as sqrt(3) instead of &radic;3, and adding unnecessary paragraph tags instead of extra spaces.
This commit is contained in:
KevinatorTrainer5
2018-11-18 14:53:17 +11:00
committed by Christopher McCormack
parent e026410609
commit ad39f4a8d9

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@ -3,42 +3,45 @@ title: Simplifying Square Roots
--- ---
## Simplifying Square Roots ## Simplifying Square Roots
Simplied Radical form: Let's say you have the radical &radic;363, and you need to simplify it into a both, simplest number, and a number that you can use in specific calculations, where we can do this by trying to find perfect squares within the radical.
Let's say you have the radical SQRT(363), and you need to simplify it into both a nicer looking number and a number that you can use in specific calculations, to do this by trying to find perfect squares within the radical.
So, it's a fact that SQRT(x*y) = SQRT(x) + SQRT(y) So, it's a fact that:
and this fact allows us to seperate the SQRT(243) into pieces
but first, we need to find a factor of 363, tha would allow us to pull a perfect square from it. &radic;(x&times;y) = &radic;x &times; &radic;y
Perfect squares include 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144... because each of them has a sqare root that is a whole number
Now, factors of 363 are: and this fact allows us to understand that we can seperate the &radic;xy into two separate radicals, &radic;x and &radic;y.
1, 3, 11, 33, 121 and 363
If you look, you can see that 121 is among that list, 121*3 is 363, and we can change the radical to show that: But first, we need to find a factor of 363, that would allow us to pull a perfect square from it.
SQRT(363) = SQRT(121*3) Perfect square numbers include: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144 etc. ,as each of them can become a whole number if these numbers were square rooted.
= SQRT(121)*SQRT(3)
And we can take the square root of 121, and make it a whole number:
= 11*Sqrt(3)
And that's your radical.
Now, factors of 363 are: 1, 3, 11, 33, 121 and 363.
If you look, you can see that 121 is among that list, 121&times;3 is 363, and we can change the radical to show that:
Simplifying Square roots in the denominator: &radic;363 = &radic;(121&times;3) = &radic;121 &times; &radic;3
And we can take the square root of 121, where we can turn it into a whole number:
= 11 &times; &radic;3
Hence, 11&radic;3 is the square root number of 363.
## Simplifying Square roots in the Denominator:
Lets' say you have the expression: Lets' say you have the expression:
2
------- <sup>2</sup>&frasl;<sub>&radic;5</sub>
SQRT(5)
And you wanted to simplify this by removing the radical from the denominator, well you can do this by multiplying this fraction by: And you wanted to simplify this by removing the radical from the denominator, well you can do this by multiplying this fraction by:
SQRT(5)
------- <sup>&radic;5</sup>&frasl;<sub>&radic;5</sub>
SQRT(5)
Which is equal to one, and you get: Which is equal to one, and you get:
2 SQRT(5) 2 x SQRT(5)
------- x ------- = ----------- because a square root multiplied by itself is the number in the square, the denominator is now a <sup>2</sup>&frasl;<sub>&radic;5</sub> &times; <sup>&radic;5</sup>&frasl;<sub>&radic;5</sub>
SQRT(5) SQRT(5) 5 whole number, not a radical. The radical still exists in the top, but this is fine in most cases.
= <sup>2&radic;5</sup>&frasl;<sub>5</sub>
because a square root multiplied by itself is the number in the square, the denominator is now a whole number, not a radical anymore. The radical still exists in the top, but this is fine in most cases, as the value itself is still exact.
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