Equation symbol changes and formatting changes (#22049)

* Equation symbol changes and formatting changes

-Initially, SQRT(value) does not actually create a square root symbol, so I decided to use replace SQRT( ) with √ next to the number, which has successfully created the square root symbol to the left of the number.
-Given that the information of the article was unorganized through jumbled information, I decided to use the paragraph tag, <p>, to make the article have an organized structure.
-I also used the biggest headline tag, <h1>, to outline the topics of square roots 
-Given that '-----' was not an effective method of creating fractions, I decided to use the fraction slash tag, "&frasl;", the superscript element, <sup>, and the subscript element, <sub>, in order to create suitable fractions

* Removing unnecessary coding and editing content

-I just double checked this content, and realized that there were a couple of mistakes such as an extra heading, putting a square root as sqrt(3) instead of &radic;3, and adding unnecessary paragraph tags instead of extra spaces.
This commit is contained in:
KevinatorTrainer5
2018-11-18 14:53:17 +11:00
committed by Christopher McCormack
parent e026410609
commit ad39f4a8d9

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@ -3,42 +3,45 @@ title: Simplifying Square Roots
---
## Simplifying Square Roots
Simplied Radical form:
Let's say you have the radical SQRT(363), and you need to simplify it into both a nicer looking number and a number that you can use in specific calculations, to do this by trying to find perfect squares within the radical.
Let's say you have the radical &radic;363, and you need to simplify it into a both, simplest number, and a number that you can use in specific calculations, where we can do this by trying to find perfect squares within the radical.
So, it's a fact that SQRT(x*y) = SQRT(x) + SQRT(y)
and this fact allows us to seperate the SQRT(243) into pieces
So, it's a fact that:
but first, we need to find a factor of 363, tha would allow us to pull a perfect square from it.
Perfect squares include 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144... because each of them has a sqare root that is a whole number
&radic;(x&times;y) = &radic;x &times; &radic;y
Now, factors of 363 are:
1, 3, 11, 33, 121 and 363
and this fact allows us to understand that we can seperate the &radic;xy into two separate radicals, &radic;x and &radic;y.
If you look, you can see that 121 is among that list, 121*3 is 363, and we can change the radical to show that:
SQRT(363) = SQRT(121*3)
= SQRT(121)*SQRT(3)
And we can take the square root of 121, and make it a whole number:
= 11*Sqrt(3)
And that's your radical.
But first, we need to find a factor of 363, that would allow us to pull a perfect square from it.
Perfect square numbers include: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144 etc. ,as each of them can become a whole number if these numbers were square rooted.
Now, factors of 363 are: 1, 3, 11, 33, 121 and 363.
If you look, you can see that 121 is among that list, 121&times;3 is 363, and we can change the radical to show that:
Simplifying Square roots in the denominator:
&radic;363 = &radic;(121&times;3) = &radic;121 &times; &radic;3
And we can take the square root of 121, where we can turn it into a whole number:
= 11 &times; &radic;3
Hence, 11&radic;3 is the square root number of 363.
## Simplifying Square roots in the Denominator:
Lets' say you have the expression:
2
-------
SQRT(5)
<sup>2</sup>&frasl;<sub>&radic;5</sub>
And you wanted to simplify this by removing the radical from the denominator, well you can do this by multiplying this fraction by:
SQRT(5)
-------
SQRT(5)
<sup>&radic;5</sup>&frasl;<sub>&radic;5</sub>
Which is equal to one, and you get:
2 SQRT(5) 2 x SQRT(5)
------- x ------- = ----------- because a square root multiplied by itself is the number in the square, the denominator is now a
SQRT(5) SQRT(5) 5 whole number, not a radical. The radical still exists in the top, but this is fine in most cases.
<sup>2</sup>&frasl;<sub>&radic;5</sub> &times; <sup>&radic;5</sup>&frasl;<sub>&radic;5</sub>
= <sup>2&radic;5</sup>&frasl;<sub>5</sub>
because a square root multiplied by itself is the number in the square, the denominator is now a whole number, not a radical anymore. The radical still exists in the top, but this is fine in most cases, as the value itself is still exact.
#### More Information:
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