freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/basic-javascript/multiple-identical-options-in-switch-statements.md

id, challengeType, videoUrl, forumTopicId, localeTitle

id	challengeType	videoUrl	forumTopicId	localeTitle
56533eb9ac21ba0edf2244df	1	https://scrimba.com/c/cdBKWCV	18242	在 Switch 语句添加多个相同选项

Description

如果你忘了给switch的每一条case添加break，那么直到遇见break为止，后续的case会一直执行。如果你想为多个不同的输入设置相同的结果，可以这样写：

switch(val) {
  case 1:
  case 2:
  case 3:
    result = "1, 2, or 3";
    break;
  case 4:
    result = "4 alone";
}

这样，1、2、3 都会有相同的结果。

Instructions

请写一个switch语句，根据输入的val的范围得出对应的answer：
1-3 - "Low"
4-6 - "Mid"
7-9 - "High" 提示：
你的case应基于范围中的每一个数字编写。

Tests

tests:
  - text: <code>sequentialSizes(1)</code>应该返回 "Low"。
    testString: assert(sequentialSizes(1) === "Low");
  - text: <code>sequentialSizes(2)</code>应该返回 "Low"。
    testString: assert(sequentialSizes(2) === "Low");
  - text: <code>sequentialSizes(3)</code>应该返回 "Low"。
    testString: assert(sequentialSizes(3) === "Low");
  - text: <code>sequentialSizes(4)</code>应该返回 "Mid"。
    testString: assert(sequentialSizes(4) === "Mid");
  - text: <code>sequentialSizes(5)</code>应该返回 "Mid"。
    testString: assert(sequentialSizes(5) === "Mid");
  - text: <code>sequentialSizes(6)</code>应该返回 "Mid"。
    testString: assert(sequentialSizes(6) === "Mid");
  - text: <code>sequentialSizes(7)</code>应该返回 "High"。
    testString: assert(sequentialSizes(7) === "High");
  - text: <code>sequentialSizes(8)</code>应该返回 "High"。
    testString: assert(sequentialSizes(8) === "High");
  - text: <code>sequentialSizes(9)</code>应该返回 "High"。
    testString: assert(sequentialSizes(9) === "High");
  - text: 你不应使用<code>if</code>或<code>else</code>语句。
    testString: assert(!/else/g.test(code) || !/if/g.test(code));
  - text: 你应该编写 9 个<code>case</code>语句。
    testString: assert(code.match(/case/g).length === 9);

Challenge Seed

function sequentialSizes(val) {
  var answer = "";
  // Only change code below this line



  // Only change code above this line
  return answer;
}

// Change this value to test
sequentialSizes(1);

Solution

function sequentialSizes(val) {
  var answer = "";

  switch(val) {
    case 1:
    case 2:
    case 3:
      answer = "Low";
      break;
    case 4:
    case 5:
    case 6:
      answer = "Mid";
      break;
    case 7:
    case 8:
    case 9:
      answer = "High";
  }

  return answer;
}