freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/basic-javascript/use-bracket-notation-to-find-the-nth-to-last-character-in-a-string.md
Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

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id, title, challengeType, videoUrl, forumTopicId, dashedName
id title challengeType videoUrl forumTopicId dashedName
bd7123c9c452eddfaeb5bdef 使用方括号查找字符串中的第N个字符到最后一个字符 1 https://scrimba.com/c/cw4vkh9 18344 use-bracket-notation-to-find-the-nth-to-last-character-in-a-string

--description--

我们既可以获取字符串的最后一个字符也可以用获取字符串的倒数第N个字符。

例如,你可以这样firstName[firstName.length - 3]操作来获得var firstName = "Charles"字符串中的倒数第三个字符。

--instructions--

使用方括号来获得lastName字符串中的倒数第二个字符。

提示
如果你遇到困难了,不妨看看thirdToLastLetterOfFirstName变量是如何做到的。

--hints--

secondToLastLetterOfLastName应该是"c"。

assert(secondToLastLetterOfLastName === 'c');

你需要使用.length获取倒数第二个字符。

assert(code.match(/\.length/g).length === 2);

--seed--

--after-user-code--

(function(v){return v;})(secondToLastLetterOfLastName);

--seed-contents--

// Setup
var lastName = "Lovelace";

// Only change code below this line
var secondToLastLetterOfLastName = lastName; // Change this line

--solutions--

var lastName = "Lovelace";
var secondToLastLetterOfLastName = lastName[lastName.length - 2];