Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

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---
id: 5900f36e1000cf542c50fe80
title: 问题13和5的倍数
challengeType: 5
videoUrl: ''
dashedName: problem-1-multiples-of-3-and-5
---
# --description--
如果我们列出所有10以下是3或5的倍数的自然数我们会得到356和9。这些倍数的总和是23。
求出所有在`number`以下的3或5的倍数的总和。
# --hints--
`multiplesOf3and5(1000)`应该返回233168。
```js
assert.strictEqual(multiplesOf3and5(1000), 233168);
```
`multiplesOf3and5(49)`应该返回543。
```js
assert.strictEqual(multiplesOf3and5(49), 543);
```
`multiplesOf3and5(19564)`应该返回89301183。
```js
assert.strictEqual(multiplesOf3and5(19564), 89301183);
```
您的函数未使用我们的测试值返回正确的结果。
```js
assert.strictEqual(multiplesOf3and5(8456), 16687353);
```
# --seed--
## --seed-contents--
```js
function multiplesOf3and5(number) {
return true;
}
multiplesOf3and5(1000);
```
# --solutions--
```js
const multiplesOf3and5 = (number) => {
var total = 0;
for(var i = 0; i < number; i++) {
if(i % 3 == 0 || i % 5 == 0) {
total += i;
}
}
return total;
};
```