* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
1.1 KiB
1.1 KiB
id, title, challengeType, videoUrl, dashedName
id | title | challengeType | videoUrl | dashedName |
---|---|---|---|---|
5900f38b1000cf542c50fe9e | 问题31:硬币总和 | 5 | problem-31-coin-sums |
--description--
在英格兰,货币由英镑,英镑和便士p组成,并且有八种普通硬币流通:
1p,2p,5p,10p,20p,50p,£1(100p)和£2(200p)。
可以通过以下方式赚取£2:
1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p
使用任意数量的硬币可以制成多少种便士?
--hints--
digitnPowers(50)
应该返回451。
assert(coinSums(50) == 451);
digitnPowers(100)
应该返回4563。
assert(coinSums(100) == 4563);
digitnPowers(150)
应该返回21873。
assert(coinSums(150) == 21873);
digitnPowers(200)
应该返回73682。
assert(coinSums(200) == 73682);
--seed--
--seed-contents--
function coinSums(n) {
return n;
}
coinSums(200);
--solutions--
const coinSums = (n) => {
const getWays = (n, m=8, c=[1, 2, 5, 10, 20, 50, 100, 200]) => {
if (n === 0) return 1;
if (m === 0 || n < 0) return 0;
return getWays(n - c[m - 1], m, c) + getWays(n, m - 1, c);
};
return getWays(n);
};