* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
72 lines
1.1 KiB
Markdown
72 lines
1.1 KiB
Markdown
---
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id: 5900f38b1000cf542c50fe9e
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title: 问题31:硬币总和
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challengeType: 5
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videoUrl: ''
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dashedName: problem-31-coin-sums
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---
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# --description--
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在英格兰,货币由英镑,英镑和便士p组成,并且有八种普通硬币流通:
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1p,2p,5p,10p,20p,50p,£1(100p)和£2(200p)。
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可以通过以下方式赚取£2:
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1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p
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使用任意数量的硬币可以制成多少种便士?
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# --hints--
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`digitnPowers(50)`应该返回451。
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```js
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assert(coinSums(50) == 451);
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```
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`digitnPowers(100)`应该返回4563。
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```js
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assert(coinSums(100) == 4563);
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```
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`digitnPowers(150)`应该返回21873。
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```js
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assert(coinSums(150) == 21873);
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```
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`digitnPowers(200)`应该返回73682。
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```js
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assert(coinSums(200) == 73682);
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```
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# --seed--
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## --seed-contents--
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```js
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function coinSums(n) {
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return n;
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}
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coinSums(200);
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```
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# --solutions--
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```js
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const coinSums = (n) => {
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const getWays = (n, m=8, c=[1, 2, 5, 10, 20, 50, 100, 200]) => {
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if (n === 0) return 1;
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if (m === 0 || n < 0) return 0;
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return getWays(n - c[m - 1], m, c) + getWays(n, m - 1, c);
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};
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return getWays(n);
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};
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```
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