* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
873 B
873 B
id, title, challengeType, videoUrl, dashedName
id | title | challengeType | videoUrl | dashedName |
---|---|---|---|---|
5900f3b21000cf542c50fec5 | 问题70欧拉置换 | 5 | problem-70-totient-permutation |
--description--
Euler的Totient函数φ(n)[有时称为phi函数]用于确定小于或等于n的正数的数量,它们是n的相对素数。例如,如1,2,4,5,7和8都小于9且相对素数为9,φ(9)= 6.数字1被认为是每个正数的相对素数,所以φ(1)= 1。有趣的是,φ(87109)= 79180,可以看出87109是79180的置换。找到n的值,1 <n <107,其中φ(n)是n的置换和比率n / φ(n)产生最小值。
--hints--
euler70()
应该返回8319823。
assert.strictEqual(euler70(), 8319823);
--seed--
--seed-contents--
function totientPermutation() {
return true;
}
totientPermutation();
--solutions--
// solution required