ee1e8abd87
* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
114 lines
2.5 KiB
Markdown
114 lines
2.5 KiB
Markdown
---
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id: 5a23c84252665b21eecc7e84
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title: Greatest subsequential sum
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challengeType: 5
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forumTopicId: 302278
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dashedName: greatest-subsequential-sum
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---
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# --description--
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Given a sequence of integers, find a continuous subsequence which maximizes the sum of its elements, that is, the elements of no other single subsequence add up to a value larger than this one.
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An empty subsequence is considered to have the sum of \\( 0 \\); thus if all elements are negative, the result must be the empty sequence.
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# --hints--
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`maximumSubsequence` should be a function.
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```js
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assert(typeof maximumSubsequence == 'function');
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```
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`maximumSubsequence([ 1, 2, -1, 3, 10, -10 ])` should return an array.
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```js
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assert(Array.isArray(maximumSubsequence([1, 2, -1, 3, 10, -10])));
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```
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`maximumSubsequence([ 1, 2, -1, 3, 10, -10 ])` should return `[ 1, 2, -1, 3, 10 ]`.
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```js
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assert.deepEqual(maximumSubsequence([1, 2, -1, 3, 10, -10]), [1, 2, -1, 3, 10]);
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```
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`maximumSubsequence([ 0, 8, 10, -2, -4, -1, -5, -3 ])` should return `[ 0, 8, 10 ]`.
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```js
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assert.deepEqual(maximumSubsequence([0, 8, 10, -2, -4, -1, -5, -3]), [
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0,
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8,
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10
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]);
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```
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`maximumSubsequence([ 9, 9, -10, 1 ])` should return `[ 9, 9 ]`.
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```js
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assert.deepEqual(maximumSubsequence([9, 9, -10, 1]), [9, 9]);
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```
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`maximumSubsequence([ 7, 1, -5, -3, -8, 1 ])` should return `[ 7, 1 ]`.
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```js
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assert.deepEqual(maximumSubsequence([7, 1, -5, -3, -8, 1]), [7, 1]);
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```
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`maximumSubsequence([ -3, 6, -1, 4, -4, -6 ])` should return `[ 6, -1, 4 ]`.
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```js
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assert.deepEqual(maximumSubsequence([-3, 6, -1, 4, -4, -6]), [6, -1, 4]);
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```
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`maximumSubsequence([ -1, -2, 3, 5, 6, -2, -1, 4, -4, 2, -1 ])` should return `[ 3, 5, 6, -2, -1, 4 ]`.
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```js
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assert.deepEqual(maximumSubsequence([-1, -2, 3, 5, 6, -2, -1, 4, -4, 2, -1]), [
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3,
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5,
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6,
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-2,
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-1,
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4
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]);
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```
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# --seed--
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## --seed-contents--
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```js
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function maximumSubsequence(population) {
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}
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```
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# --solutions--
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```js
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function maximumSubsequence(population) {
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function sumValues(arr) {
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var result = 0;
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for (var i = 0, len = arr.length; i < len; i++) {
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result += arr[i];
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}
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return result;
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}
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var greatest;
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var maxValue = 0;
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for (var i = 0, len = population.length; i < len; i++) {
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for (var j = i; j <= len; j++) {
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var subsequence = population.slice(i, j);
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var value = sumValues(subsequence);
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if (value > maxValue) {
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maxValue = value;
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greatest = subsequence;
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};
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}
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}
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return greatest;
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}
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```
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